3.1525 \(\int \frac{x^9}{\sqrt{1+x^8}} \, dx\)

Optimal. Leaf size=62 \[ \frac{1}{6} x^2 \sqrt{x^8+1}-\frac{\left (x^4+1\right ) \sqrt{\frac{x^8+1}{\left (x^4+1\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (x^2\right ),\frac{1}{2}\right )}{12 \sqrt{x^8+1}} \]

[Out]

(x^2*Sqrt[1 + x^8])/6 - ((1 + x^4)*Sqrt[(1 + x^8)/(1 + x^4)^2]*EllipticF[2*ArcTan[x^2], 1/2])/(12*Sqrt[1 + x^8
])

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Rubi [A]  time = 0.0239049, antiderivative size = 62, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {275, 321, 220} \[ \frac{1}{6} x^2 \sqrt{x^8+1}-\frac{\left (x^4+1\right ) \sqrt{\frac{x^8+1}{\left (x^4+1\right )^2}} F\left (2 \tan ^{-1}\left (x^2\right )|\frac{1}{2}\right )}{12 \sqrt{x^8+1}} \]

Antiderivative was successfully verified.

[In]

Int[x^9/Sqrt[1 + x^8],x]

[Out]

(x^2*Sqrt[1 + x^8])/6 - ((1 + x^4)*Sqrt[(1 + x^8)/(1 + x^4)^2]*EllipticF[2*ArcTan[x^2], 1/2])/(12*Sqrt[1 + x^8
])

Rule 275

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Dist[1/k, Subst[Int[x^((m
+ 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rule 220

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[((1 + q^2*x^2)*Sqrt[(a + b*x^4)/(a*(
1 + q^2*x^2)^2)]*EllipticF[2*ArcTan[q*x], 1/2])/(2*q*Sqrt[a + b*x^4]), x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rubi steps

\begin{align*} \int \frac{x^9}{\sqrt{1+x^8}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x^4}{\sqrt{1+x^4}} \, dx,x,x^2\right )\\ &=\frac{1}{6} x^2 \sqrt{1+x^8}-\frac{1}{6} \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+x^4}} \, dx,x,x^2\right )\\ &=\frac{1}{6} x^2 \sqrt{1+x^8}-\frac{\left (1+x^4\right ) \sqrt{\frac{1+x^8}{\left (1+x^4\right )^2}} F\left (2 \tan ^{-1}\left (x^2\right )|\frac{1}{2}\right )}{12 \sqrt{1+x^8}}\\ \end{align*}

Mathematica [C]  time = 0.007882, size = 34, normalized size = 0.55 \[ \frac{1}{6} x^2 \left (\sqrt{x^8+1}-\, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};-x^8\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x^9/Sqrt[1 + x^8],x]

[Out]

(x^2*(Sqrt[1 + x^8] - Hypergeometric2F1[1/4, 1/2, 5/4, -x^8]))/6

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Maple [C]  time = 0.022, size = 30, normalized size = 0.5 \begin{align*}{\frac{{x}^{2}}{6}\sqrt{{x}^{8}+1}}-{\frac{{x}^{2}}{6}{\mbox{$_2$F$_1$}({\frac{1}{4}},{\frac{1}{2}};\,{\frac{5}{4}};\,-{x}^{8})}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^9/(x^8+1)^(1/2),x)

[Out]

1/6*x^2*(x^8+1)^(1/2)-1/6*x^2*hypergeom([1/4,1/2],[5/4],-x^8)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{9}}{\sqrt{x^{8} + 1}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^9/(x^8+1)^(1/2),x, algorithm="maxima")

[Out]

integrate(x^9/sqrt(x^8 + 1), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{9}}{\sqrt{x^{8} + 1}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^9/(x^8+1)^(1/2),x, algorithm="fricas")

[Out]

integral(x^9/sqrt(x^8 + 1), x)

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Sympy [C]  time = 0.845997, size = 29, normalized size = 0.47 \begin{align*} \frac{x^{10} \Gamma \left (\frac{5}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{5}{4} \\ \frac{9}{4} \end{matrix}\middle |{x^{8} e^{i \pi }} \right )}}{8 \Gamma \left (\frac{9}{4}\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**9/(x**8+1)**(1/2),x)

[Out]

x**10*gamma(5/4)*hyper((1/2, 5/4), (9/4,), x**8*exp_polar(I*pi))/(8*gamma(9/4))

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{9}}{\sqrt{x^{8} + 1}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^9/(x^8+1)^(1/2),x, algorithm="giac")

[Out]

integrate(x^9/sqrt(x^8 + 1), x)